41 lines
1.6 KiB
Python
41 lines
1.6 KiB
Python
|
#
|
||
|
|
# Sam Hadow - Huffman-py
|
||
|
|
# Copyright (C) 2023
|
||
|
|
#
|
||
|
|
# This program is free software: you can redistribute it and/or modify
|
||
|
|
# it under the terms of the GNU General Public License as published by
|
||
|
|
# the Free Software Foundation, either version 3 of the License, or
|
||
|
|
# (at your option) any later version.
|
||
|
|
#
|
||
|
|
# This program is distributed in the hope that it will be useful,
|
||
|
|
# but WITHOUT ANY WARRANTY; without even the implied warranty of
|
||
|
|
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
|
||
|
|
# GNU General Public License for more details.
|
||
|
|
#
|
||
|
|
# You should have received a copy of the GNU General Public License
|
||
|
|
# along with this program. If not, see <http://www.gnu.org/licenses/>.
|
||
|
|
#
|
||
|
|
def calcul_code(node, value = '', les_codes = None):
|
||
|
|
# on crée le dict des codes s'il n'existe pas encore (lors du premier passage dans la fonction)
|
||
|
|
if les_codes == None:
|
||
|
|
les_codes = dict()
|
||
|
|
|
||
|
|
# gérer le cas où on a qu'un seul noeud, on lui attribuera le code 0 par défaut
|
||
|
|
# à noter que dans ce cas là l'algorithme d'Huffman pour la compression est peu utile
|
||
|
|
if(not node.left and not node.right):
|
||
|
|
les_codes[node.lettres] = "0"
|
||
|
|
return les_codes
|
||
|
|
|
||
|
|
#code pour le sommet actuel
|
||
|
|
newValue = value + str(node.code)
|
||
|
|
|
||
|
|
if(node.left):
|
||
|
|
calcul_code(node.left, newValue, les_codes)
|
||
|
|
if(node.right):
|
||
|
|
calcul_code(node.right, newValue, les_codes)
|
||
|
|
|
||
|
|
if(not node.left and not node.right):
|
||
|
|
les_codes[node.lettres] = newValue
|
||
|
|
|
||
|
|
return les_codes
|